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5.DF2中的白花植株占37/64,红花植株占27/64(3/4的3次方),可知F1的基因型很可能是 AaBbCc,而且三对基因之间自由组合。A每对基因的遗传均遵循分离定律,A正确。B.根据分析,该植物花色的遗传符合自由组合定律,至少受3对等位基因控制;如果还有第4对或更多基因,都是显性纯合的,B正确。C.在F2中,红花占27/64,其中有1/64的个体( AABBCO)是纯合体,即F2红花中纯合子占1/27,则有26/27的个体是杂合体,C正确。D.由于每对等位基因都至少含有一个显性基因时才开红花,所以F2红花植株中纯合子( AABBCC)基因型只有1种,白花植株中纯合子基因型有23-1=7种,D错误。
书面表达Dear Mr JohnsonIm Li Hua, a student of English Association. I'm writing to invite you to be a judge at ourEnglish speech contest to be held next Wednesday.The English speech contest will start at 2: 00 pm in our school lecture hall and will last forabout three hours. Ten students who finally get the chance to give the speech are chosen fromdifferent classes. They will deliver their speeches on the given topic "Beauty in our heart. You canscore them according to their performances.We would appreciate it if you could accept our invitation I am looking forward to your reply.Yours