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【22~23题答案】【答案1p=sin80e[0,x小.(名(3):(2)2.【解析】【分析】(1)根据圆的极坐标方程求出C2,联立曲线C和曲线C2的方程求交点即可:(2)写出C的极坐标方程,求出M,N的极坐标,由极坐标的意义求线段MN的长度【小问1详解】曲线C,的极坐标方程为p=sin0(0e[O,πD.与G方程联立代入得s血8=1-s血8,$血0=2解得9=名或0-5π66故所求交点坐标分别为兮名(爱【小问2详解】因为曲线G为过原点倾斜角是的直线,故其极坐标方程为日=兀和日=4π33曲线C与C的方程,解得两交点的股坐标分别为M0-,N0 ),红23所以aHoN1 1oN0-9 0 -=2选修4一5:不等式选讲
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