衡水金卷先享题高三一轮复习语文周测卷九 答案

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第二节书面表达（满分25分）【参考范文】The campus activity that benefits me mostIt is well known that my school has held a large number of activities in the past three years,which benefits usstudents a lot.From my perspective,the most beneficial one is "Long distance Running for Love"organized by the StudentsUnion when I was a freshman.And the money collected by this activity is contributed to the Project Hope.It isreally my honor to participate the long running,because it benefits me greatly not only in body but also in mind.In conclusion,although I have taken part in many campus activities,I think the running for love mostbeneficial to me.And I am looking forward to that more wonderful and meaningful activities will be held in ourcampus.

15.解：(1)A与B发生弹性正碰根据动量守恒有m1=1y'十m2vB(1分)》根据机被能守恒有之m=2m02m2g2(1分解得v'=-3m/s,vg=6m/s(2分)设B通过竖直圆形轨道最高点时速度为vm跟据机械能守恒有mg·2R=2mU22n2n2(1分)》2B通过最高点时，根据牛顿第二定律有m2g=m:R(1分)联立解得R=0.72m。(2分)(2)B滑上传送带先做减速运动，后做反向的加速运动B的加速度大小a=g=2m/s2(1分)设经过t时间，B的速度减为零根据运动学公式可知t==3s(1分)a根据对称性可知，B反向加速运动的时间也是3s,离开传送带时的速度大小为gB在传送带上与传送带发生的相对位移△x=2t=48m(2分)B在传送带上运行时产生的热量Q=2g△x=19.2J。(2分）(3)由于B离开传送带时的速度大小为VB,故B恰好能再次通过圆形轨道B通过圆形轨道后向左运动，追上A与之发生弹性碰撞根据动量守恒有m1U1'一m2vB=m1y十2vB(1分)根据机被能守恒有号？十分m:w°-之7n1012十 2722B2(1分)联立解得"=一7m/s,vg'=一4m/s(另一组解不合题意舍去)(1分)所以B最终的速度大小为4m/s,方向水平向左。(1分)