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第四部分写作第一节应用文写作【写作指导】本文是一封电子邮件,要求考生告知留学生George他没有通过上周京剧社的面试。根据题目要求可将本文写作内容分为三部分:一是告知消息;二是说明面试未通过的原因;三是给予鼓励。在说明面试未通过的原因时可适当增加细节,以使行文连贯。在写作时,考生可以使用非谓语动词、定语从句等语法结构来丰富文章,以提高作文的得分档次审题:人称:第一人称和第二人称为主时态:一般现在时为主,一般将来时为辅提纲:开头句:① I'm Li Hua, chairman of the Peking OperaClub. I want to thank you for your interest in joining thePeking Opera Club and for all the time you put into theInterview process.2)Im Li Hua, chairman of the Peking Opera Club.Thanks for your interest in joining the Peking Opera Cluband for the time you put into the interview process.文章主体:要点一:① Unfortunately, m somy to tellou that we will not offer the membership to you(2 Unfortunately, Im sorry to tell you that you failed themembership interview held last week.要点二:① While your enthusiasm for Peking Opera isvery impressive, we have chosen a candidate who has morehands-on experience. Besides, your Mandarin failed to meetthe criteria for stage performance.2)Although your enthusiasm for Peking Opera is veryimpressive, we have chosen a candidate who has morepractical experience, What's more, your Mandarin failed tomeet the criteria for stage performance要点三:① However, we will keep your resume on fileand keep you in mind if there should be any other chances2 But we will keep your resume on file and inform youif there should be any other chances结尾句:① Best wishes!(2)All the best wishes for youOne possible versionDear GeorgeIm Li Hua, chairman of the Peking Opera Club. I wantto thank you for your intjoining the Peking OperaClub and for all the time you put into the interview processUnfortunately, I'm sorry to tell you that we will not offer themembership to youWhile your enthusiasm for Peking Opera is verympressive. we have chosen a candidate whomorehands-on experience. Besides, your Mandarin failthe criteria for stage performance.However, we will keep your resume on file and keep youin mind if there should be any other chances. Best wishesYoursLi Hua

19.【考查目标】必备知识:本题主要考查直三棱柱中的线线垂直、二面角的正弦值、空间向量等知识.关键能力:通过线线垂直的证明和二面角的求解考查了空间想象能力、逻辑思维能力和运算求解能力学科素养:理性思维、数学探索【解题思路】(1)先证明BA⊥BC,再利用AB,BC,BB1两两垂直建立空间直角坐标系,求出相关点的坐标,利用向量证明;(2)分别求出面BB1C1C和面DEF的一个法向量,通过求出两法向量夹角的余弦值的最大值来解决解:(1)因为E,F分别是AC和C1的中点,且AB=BC=2所以CF=1,BF=√5.如图,连接AF,由BF⊥A1B1,AB∥AB,得BF⊥AB,于是AF=BF ABF=3,所以AC=√AF-CF=2.由AB2 BC2=AC2,得BA⊥BC,故以B为坐标原点,以AB,BC,B1所在直线分别为x,y,z轴建立空间直角坐标系B-xy则B(0,0,0),E(1,1,0),F(0,2,1),BF=(0,2,1)设B1D=m(0≤m≤2),则D(m,0,2),于是DE=(1-m,1,-2)所以B.DE=0,所以BF⊥DE(2)易知面BB1C1C的一个法向量为n1=(1,0,0)设面DFE的法向量为n2=(x,y,2),n,又靂=(1-m,1,-2),E=(-1,1,1)所以(1-m)x y-2z=0-x y z=0,令x=3,得y=m 1,z=2-m,于是,面DFE的一个法向量为n2=(3,m 1,2-m),所以cos(n1,n2〉=)2设面BCC与面DFE所成的二面角为6,则in6=√1-m(n1,m2),故当m=时,面BBCC与面DFE所成的二面角的正弦值最小为,即当B1D=时,面BB1C1C与面DFE所成的二面角的正弦值最小.【解題关键】本题求解关键是建立恰当的空间直角坐标系,确定相关点的坐标,再利用空间向量进行运算