2022届炎德英才大联考联体雅礼中学答案

2022届炎德英才大联考联体雅礼中学答案，目前答案易对网已经整理了2022届炎德英才大联考联体雅礼中学答案的各科答案和试卷，更多联考试卷请关注本网站。

第二节书面表达(满分25分)One possible versionDear Peter,I am glad to receive your letter. Thanks for your concern about my recent learning status andmy travel arrangements after the college entrance examination, which I will explain respectively asWith the examination drawing near, I am now fully devoted to my study in the hope of makingmyself admitted to my dream university. As for the travel plan after the exam, I'm consideringtouring around Beijing. Not only is it an amazing city with varieties of tourist attractions, but also itis home to many top universities, which fascinates me a lot.Thanks again for your concern about me. wish me good luck in the examYLi Hu一求而事让饿朵耐(朵9FA

28.(15分)(1(1分)H2 CO--2eHO CO2(2分)(2)①CO(g) 2H2(g)=CH2OH(g)△H2226kJ,mol(2分)②0.01(2分)③ HCOOH* 2H2(g)一 H:COOH H2(g[或 HCOOH· 2H1(g)一HCOH·1(2分)(3)①L1(1分)1(或0.14)(2分)③<(1分)增大压强、分离出H2O(2分,其他合理答案也给分)【解析】(1)Si的原子结构示意图为4;负极发生氧化反应,H2在负极放电,电解质为熔融碳酸钠,负极的电极反应式为H2 CO-2e-H20 CO2。(2)①由键能数据可知,△H=2×745kJ·mol-1 3436kJ·mol-1-(3×413.4kJ·mol-1 351kJ·mol- 3×462.8kJ·mol-1)=-181.6kJ·mol-。再根据盖斯定律,总反应一反应1可得,反应2为CO(g) 2H2(g)=CH3OH(g)△H2=△H-△H222.6kJ·mol-。②由题意知,气体减小的质量为2.0g·L-1×2.0L4.0CO:(g) 3H,(g)CH, OH(I) H, O(1)Am1 mol4.0g反应消耗的二氧化碳的物质的量n=1mol×4050g=0.08mol,则0~4min内,CO2的平均反应速率为0. 08 molLX4 min0.01mol·L1.min-1③生成甲醇的决速步骤由反应历程中反应速率最慢的步骤决定,活化能越大,反应速率越慢,根据图中数据可知,活化能最大的步骤的化学方程式为HCOOH. 2H,(g)-H, COOH分H(g)HCOOH. 2H:(g)--H, COOH.理综(3)①相同条件下,H2越多,CO2的平衡转化率越高,则图3中代表c(CO2)1c(H2)=118的曲线为L②M点时进料浓度比c(CO2):c(H2)=13,设起始投入1 mol CO2、3molH2,根据三段式:2CO2(g) 6H2(g)=C2H4(g) 4H2O(g)起始(mol):1转化(ml):0.80.41.6平衡(mol):0.20.60.40.4平衡时乙烯的体积分数为0.2 0.6 0.4 1.6③由图可知,升高温度,CO2的平衡转化率降低,平衡逆向移动,则正反应为放热反应,△H<0;为提高CO2的平衡转化率,可采取的措施有增大压强、分离出H2O等